Sale!

# COMP 310/ECSE 427 Assignment #3 solution

\$30.00

COMP 310/ECSE 427

Assignment #3

1 Theoretical Questions
1. When we already use 2 semaphores in the producer-consumer problem why is there
a need for mutex?
2. Is it possible that a consumer with lowest priority su↵ers from starvation in the 2
semaphore and 1 mutex setup for producer-consumer.Explain the situation.
3. Though binary semaphores avoid starvation and mutexes don’t, why is it recommeded
to use mutex in producer-consumer to secure the critical section?

Category:

## Description

COMP 310/ECSE 427

Assignment #3

1 Theoretical Questions
1. When we already use 2 semaphores in the producer-consumer problem why is there
a need for mutex?
2. Is it possible that a consumer with lowest priority su↵ers from starvation in the 2
semaphore and 1 mutex setup for producer-consumer.Explain the situation.
3. Though binary semaphores avoid starvation and mutexes don’t, why is it recommeded
to use mutex in producer-consumer to secure the critical section?
4. Why do producer-consumer need to have 2 semaphores namely ”Full” and ”empty”.
What complications may arise if we use only one semaphore for ”Full” and rely on
computed complementary value for ”empty”.
2 Disk Scheduling Algorithm
In the given skeleton for the disk scheduling part, your task is to implement the following
algorithm for a single batch.
1. FCFS (Implemented)
2. SSTF
3. SCAN
4. C-SCAN
5. LOOK
6. C-LOOK
FCFS is the most basic algorithm which has been pre-implemented in the skeleton.
You are supposed to modify only the contents of accessPOLICY() functions corresponding to each policy.
In some policies where the disk head jumps to extremities, introduce it in the output sequence.Note that these extremities might not be present in the output sequence
depending on the input given.
The printSeqNPerformance() function takes your output sequence as an array of integers and prints it. It also computes the number of cylinders traversed considering
the cylinders traversed even when there is a jump back of head, as a result this metric will be di↵erent from what was there in the lecture slides.This metric is only for
assignment-evaluation purpose.In general cylinder traversed in jump back is not a part
of performance.
1
3 Bankers Algorithm
This part of the assignment consists of implementing a system that simulates allocating
resources to concurrent processes requesting them in such a way as to avoid deadlocks.
Processes will request resources as they need them, and will finish when they are done
requesting and being granted all their resources. If a process cannot be granted the requested resources, it will block until another process terminates and relinquishes all their
resources.
1) Question 1
You are asked to first design a system that takes as input the number of processes, the
number of district resources, the amount of each resource in the system, the maximum
resource claim per process / resource. The system will then simulate each process using
a thread, and all threads will run concurrently until they have used all the resources they
require, after which they will terminate. Every time a process thread runs, it requests
ij instances of each resource j, where i is randomly selected as a value between 0 and
the remaining amount of needed resources to terminate. It then checks if granting the
resource request will result in a safe state. If so, the resources are granted to the process
and the process continues (by sleeping for 3 seconds). Otherwise, the process is blocked.
You are to ensure that mutual exclusion / synchronization are respected at the appropriate locations using semaphores and mutexes. The flow for each process thread is thus as
follows:
1. Processes begin
2. while a process executes, a resource request vector is generated for that process.
This request vector contains ij instances of each resource j, where i is randomly
selected as a value between 0 and the remaining amount of needed resources to
terminate.
3. A deadlock avoidance algorithm is then run (Bankers) in order to check whether
allocating these resources will result in a safe state.
4. if allocation is safe, then the process acquires the resources and the can continue
executing.
5. it checks at this point if there are remaining requests to be made by that process, if
not, then the process can terminate. If there are remaining requests, then simulating
continued execution is done by sleeping for 3 seconds and then making a new request.
6. if allocation is unsafe, then the process blocks until another process finishes and
relinquishes its resources.
2) Question 2
The above system is working in ideal conditions, where the number of resources is not
changing throughout. Banker’s algorithm works under the assumption that the number
of instances of each resource does not change. We would like to see what happens when
this condition gets violated. To do so, we will now introduce faulty resources to the
2
system. This will be done through a thread called ”faulty thread”, which will run every
10 seconds, and at each run create a fault in only one of the resources (the resource is
selected randomly with a uniform probability) with a probability of 50%. If a fault occurs for a particular resource, then the number of available instances for that particular
resource is decreased by 1. Now given that the number of resources is changing over time,
Banker’s algorithm may not be able to avoid deadlock in this case.
So for this situation, though the same scheme as above will be implemented (i.e. you
will still use Banker’s algorithm to allocate resources), deadlock might still occur. You
will thus need to detect deadlock. The deadlock detection scheme we will use in this
case will be run every 10 seconds, and will check if the process needs are higher than the
available resources for all processes. If no process can acquire all the resources it needs
to complete, then deadlock is inevitable. In this case, you should output the following
and then exit:
Deadlock will occur as processes request more resources, exiting…
4 Submission guidelines
1) Theoretical Section